Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

Two masses of $10\; kg$ and $20\; kg$ respectively are connected by a massless spring. A pull of $100 N$ acts on the mass $20 kg$. If the instantaneous acceleration of 10 kg mass is $2 m/s^2$, what is the acceleration of $20 kg$ mass

\[(a)\;1 m/s^2 \quad (b)\;2 m/s^2 \quad (c)\;3 m/s^2 \quad(d)\;4 m/s^2 \]

Can you answer this question?

1 Answer

0 votes
Force on $10 kg$ mass =ma
$\qquad= 10 \times 2$
$\qquad=20 N$
Free body diagram
=> $K_x=20 N$
Therefore Force on $20 kg$ mass
$\qquad= 100-20$
$\qquad=80 N$
$\quad=4 m/s^2$
Hence d is the correct answer.


answered Jul 4, 2013 by meena.p
edited Jan 26, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App