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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A shell of mass 'M' moving with velocity 'V' suddenly explodes into two fragments. One of the mass 'm' is reduced to rest. Find the velocity of the other fragment.

\[(a)\;\frac{(M-m)}{MV} \quad (b)\;\bigg(\frac{m}{M+m}\bigg)V \quad (c)\;\bigg(\frac{m}{M-m}\bigg)V \quad(d)\;\frac{MV}{M-m} \]

1 Answer

Using law of conversations of linear momentum
Momentum before explosion =Total momentum after explosion
If $x$ is velocity of $2^{nd}$ mass
$MV=m \times 0 +(M-m)x$
$\quad x= \large\frac{MV}{M-m}$
Hence d is the correct answer.


answered Jul 5, 2013 by meena.p
edited Jan 26, 2014 by meena.p

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