This is (b) part of the multi-part question q1

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- If $y=f(x)$,then $\large\frac{dy}{dx}$ measures the rate of change of $y$ w.r.t $x$.
- $\big(\large\frac{dy}{dx}\big)_{x=x_0}$ represents the rate of change of $y$ w.r.t $x$ at $x=x_0$

Area of the circle =$\pi r^2\;cm^2$

Radius of the circle =4cm.

$A=\pi r^2$

Differentiating w.r.t $r$ we get,

$\large\frac{dA}{dr}$$=2\pi r$

Substituting for $r$ we get,

$\qquad=2\times \pi\times 4$

$\qquad=8\pi\;cm^2/cm$

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