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# A lift is moving downward with an acceleration equal to acceleration due to gravity. A body of mass M kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $\mu$, then the frictional resistance offered by the body is

$(a)\;Mg \quad (b)\;\mu Mg \quad (c)\;2 \mu Mg \quad(d)\;zero$

For downward acceleration motion of lift
$R=m(g-0)$
Since $a=g;R=0$
Therefore $F=\mu R=0$
Hence d is the correct answer.

edited Jan 26, 2014 by meena.p