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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block will be

\[(a)\;P \quad (b)\;\frac{Pm}{M+m} \quad (c)\;\frac{mp}{M+m} \quad(d)\;\frac{MP}{M+m}\]

1 Answer

Acceleration of system $=\large\frac{P}{M+m}$
Force on the block= Mass of block $\times$ acceleration of system
$\qquad= M \times \large\frac{P}{M+m}$
$\qquad=\large\frac{MP}{M+m}$
Hence d is the correct answer.

 

answered Jul 5, 2013 by meena.p
edited Jan 26, 2014 by meena.p
 

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