Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block will be

\[(a)\;P \quad (b)\;\frac{Pm}{M+m} \quad (c)\;\frac{mp}{M+m} \quad(d)\;\frac{MP}{M+m}\]

Can you answer this question?

1 Answer

0 votes
Acceleration of system $=\large\frac{P}{M+m}$
Force on the block= Mass of block $\times$ acceleration of system
$\qquad= M \times \large\frac{P}{M+m}$
Hence d is the correct answer.


answered Jul 5, 2013 by meena.p
edited Jan 26, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App