Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A body of mass 50 kg is pulled by a rope of length 8 m on a surface by a force of 108 N applied at the other end. The force that is acting on the 50 kg mass, if the linear density of rope is 0.5 kg/m will be

\[(a)\;108\; N \quad (b)\;100\; N \quad (c)\;116\; N \quad(d)\;92 \;N \]

Can you answer this question?

1 Answer

0 votes
mass of rope $=8 \times \large\frac{1}{2}$
$\qquad = 4 \;kg$
Total mass $=54 \;kg$
a-acceleration of system $=\large\frac{F}{m}$
$\qquad=\large\frac{108}{54}$$=2 m/s^2$
Force used for pulling rope $=4 \times 2=8\;N$
Therefore Force applied on mass $=108-8=100 \;N$
Hence b is the correct answer.


answered Jul 5, 2013 by meena.p
edited Jan 26, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App