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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A horizontal force F is applied on a rod inserted between two identical blocks A and B placed over a rough surface as shown.Force F is gradually increased then which of the block will move first.

$\begin{array}{1 1} (a) block A \\(b) block B \\ (c) \text{Both will move simultaneously } \\ \text{d) will depend on friction between block and ground.}\end{array}$

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1 Answer

$F_1-F_2=F$
$F_1 > F_2$
Therefore Block B will move first
Hence b is the correct answer.

 

answered Jul 8, 2013 by meena.p
edited Jan 26, 2014 by meena.p
 

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