Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A fireman has to carry an injured person of mass 40 kg from the top of a building with the help of the rope which can with stand a load of 100 kg. The acceleration of the fireman if his mass is 80 kg will be

\[(a)\;8.17 m/s^2 \quad (b)\; 9.8 m/s^2 \quad (c)\;17.97 m/s^2 \quad(d)\;1.63 m/s^2 \]

Can you answer this question?

1 Answer

0 votes
Total mass $= 80+40=120 kg$
The rope cannot withstand this load
So he has to slide down with an acceleration.
Maximum tension $=100 \times 9.8\; N$
$m(g-a)=100 \times 9.8$
$120 (9.8-a)=980$
$ =>a=1.63\; m/s^2$
Hence d is the correct answer.


answered Jul 8, 2013 by meena.p
edited Jan 26, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App