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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
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A fireman has to carry an injured person of mass 40 kg from the top of a building with the help of the rope which can with stand a load of 100 kg. The acceleration of the fireman if his mass is 80 kg will be

\[(a)\;8.17 m/s^2 \quad (b)\; 9.8 m/s^2 \quad (c)\;17.97 m/s^2 \quad(d)\;1.63 m/s^2 \]

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Total mass $= 80+40=120 kg$
The rope cannot withstand this load
So he has to slide down with an acceleration.
Maximum tension $=100 \times 9.8\; N$
$m(g-a)=100 \times 9.8$
$120 (9.8-a)=980$
$ =>a=1.63\; m/s^2$
Hence d is the correct answer.


answered Jul 8, 2013 by meena.p
edited Jan 26, 2014 by meena.p

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