\[(a)\;0.2 m \quad (b)\; 0.1 m \quad (c)\;0.05 m \quad(d)\;0.25 m \]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Free body diagram of mass 3 kg in

For the system net pulling force is due to mass B and massC

$F=(2+3) g=5 \times 10=50 N$

Totla mass to be pulled $=(1+2+3)$

$\qquad=6 kg$

Therefore $ a=\large\frac{50}{6} $$m/s^2$

From free body diagram

$30 -kx=ma$

$30-kx=3 \bigg( \large\frac{50}{6} \bigg)$

$30-kx=25$

$-kx=25-30=-5$

$x=\large\frac{5}{R}$

$\quad= \large\frac{5}{50}$

$\quad=0.1$

Hence b is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...