Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

All surfaces are smooth in the figure. Find F such that block of mass m resting on a wedge of mass M remains stationary with respect to wedge

a) $(M-m) g \tan \theta$ b) $Mg \tan \theta$ c) $\frac{M}{m} g \tan \theta$ d) $(M+m) g \tan \theta $

Can you answer this question?

1 Answer

0 votes
Free body diagram of block of mass m
The block moves with acceleration a w.r.t ground
$a= \large\frac{F}{M+m}$
$\Sigma F_y=0=>N \cos \theta=mg$
$\Sigma F_x=0=>N \sin \theta=ma$
$a= g \tan \theta$
$F= a(M+m)$
$\quad=g \tan \theta(M+m)$
Hence d is the correct answer.
answered Jul 8, 2013 by meena.p
edited May 26, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App