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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

Inside a horizontally moving box, a man finds that when an object is placed on a horizontal smooth table and released; it moves with an acceleration $10 m/s^2$ In this box if 1 kg body is suspended with a light string, the tension in the string in equilibrium position $(g=10 m/s^2)$

\[(a)\;10 \;N \quad (b)\; 10\;\sqrt 2 \;N \quad (c)\;20 \;N \quad(d)\;zero \]

1 Answer

Since the object slides with acceleration $10 m/s^2$ the acceleration of box is $10 m/s^2$
Inside the box a body suspended experiences a pseudo force
Therefore $T=\sqrt {(mg)^2+(ma)^2}$
$\qquad=\sqrt {10 ^2+10^2}$
$\qquad=10 \sqrt 2 N$
Hence b is the correct answer.


answered Jul 9, 2013 by meena.p
edited Jan 26, 2014 by meena.p

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