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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
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A horizontal force of 10 N is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and wall is $\mu$ The weight of the block is

\[(a)\;50\;N \quad (b)\; 100\;N \quad (c)\;20\;N \quad(d)\;2\;N\]

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Normal reaction $N=10 N$
Maximum friction $=\mu N$
$\qquad=0.2 \times 10=2N$
for equilibrium
weight =2N
Hence d is the correct answer.
answered Jul 9, 2013 by meena.p
edited May 27, 2014 by lmohan717

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