Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A horizontal force of 10 N is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and wall is $\mu$ The weight of the block is

\[(a)\;50\;N \quad (b)\; 100\;N \quad (c)\;20\;N \quad(d)\;2\;N\]

Can you answer this question?

1 Answer

0 votes
Normal reaction $N=10 N$
Maximum friction $=\mu N$
$\qquad=0.2 \times 10=2N$
for equilibrium
weight =2N
Hence d is the correct answer.
answered Jul 9, 2013 by meena.p
edited May 27, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App