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# Calculate the accelerating potential that must be applied to a proton beam to give it an effective wavelength of 0.005 nm.

$\begin{array}{1 1}(a)\;30\; volt\\(b)\;32.85\; volt\\(c)\;35.65\;volt\\(d)\;43.6\;volt\end{array}$

$v = \frac{h}{m}\lambda$
$ev =\frac{1}{2}mv^2$