a) 5 kg b) 10 kg c) 20 kg d) 15 kg

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Since A and B are stationary the net force on each is zero.

Let m be mass of C and $m_1$ mass of A

At $A$: $N=(m+m_1)g$

$f=\mu N$

$\quad= \mu _s(m_1+m)g$-----(1)

At $B$ :$ \;T=m_2 g$-----(2)

from (1) and (2)

$m_2 g=\mu_s (m_1+m)g$

$m=\Large\frac{m_2-\mu _s m_1}{\mu _s}$

$\quad=\Large\frac{m_2}{\mu_s}$$-m_1$

$\quad=\large\frac{5}{0.2}$$-10$

$\quad=15 \;kg$

Hence d is the correct answer

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