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# Find energy of each of the photons which correspond to light of frequency $3\times 10^{15}Hz$.

$\begin{array}{1 1}(a)\;1.988 \times 10^{–18}J\\(b)\;1.988 \times 10^{–10}J\\(c)\;0.988 \times 10–18J\\(d)\;1.988 \times 10–28J\end{array}$

$Energy (E) of\; a\; photon\; is\; given\; by\; the\; expression, E =\frac{h}{mu}$
$h = Planck’s\;constant = 6.626 \times 10–34Js$
$ν = frequency \;of\; light = 3 \times 10^{15}Hz$
$Substituting \;the\; values\; in \;the\; given\; expression\; of\; E:$
$E = (6.626 \times 10^{–34}) (3 \times 10^{15})$
$E = 1.988 \times 10^{–18}J$