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# A car battery of emf 12 V and internal resistance $5\times10^{-2}\Omega$, receives a current of 60 Å from external source, then terminal voltage of battery is :

( A ) 15 v
( B ) 20 V
( C ) 9 V
( D ) 12 v

$V= E+IR$
$\qquad= 12+60 \times 5 \times 10^{-2}$
$\qquad= 12+3$
$\qquad= 15\;V$