Comment
Share
Q)

# In a Bohr's model of atom when an electron jumps from n=1 to n=3 how much energy will be emitted or absorbed

$\begin{array}{1 1}(a)\;2.15\times10-11erg\\(b)\;0.1911\times10-10erg\\(c)\;2.389\times10-12erg\\(d)\;0.239\times10-10erg\end{array}$

$\triangle E=E1−E3$
$=2.179\times10^{-11}-\frac{2.179\times10^{11}}{9}$
$=\frac{8}{9}\times2.179\times10^{-11}$
$=1.91\times10^{-11}$
$=0.191\times10^{-10}$