Ask Questions, Get Answers

Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A nozzle is discharging water at a rate of 200 litre per second with a speed of 10 m per second. If the water strikes a wall at right angles and does not bounce of the wall, find the force F newton exerted by the wall on water. mass of 1 litre of the water is 1kg

\[(a)\;2 \times 10^3 N \quad (b)\;3 \times 10^3 N \quad (c)\;4 \times 10^2 N \quad (d)\;3 \times 10^2 N \]

1 Answer

Mass of water =200 kg
momentum destroyed per second =mv
$=200 \times 10\; kg \;m/s$
Impulse =change in momentum
$F \times 1\; NS=2000$
$F=2 \times 10 ^3 N$
Hence a is the correct answer. 


answered Jul 11, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions