logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

Suppose that a shoelace passes without friction through 5 holes on each side of your shoe. If the tension in that shoe lace is 10 N, how much total force is the shoelace exerting on the right side of your shoe?

\[(a)\;10 \;N\quad (b)\;100\;N \quad (c)\;50 \;N \quad (d)\;25\;N \]

Can you answer this question?
 
 

1 Answer

0 votes
Each segement of the lace pulls on the right side of your shoe with 10 N.
Since there are 5 holes and each hole has two segements, total segement of right side=10.
Total force $=10 \times 10 N $
$\qquad\qquad=100 N$
Hence b is the correct answer

 

answered Jul 11, 2013 by meena.p
edited Feb 10, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...