\[(a)\;16 kg\quad (b)\;10 kg \quad (c)\;18 kg \quad (d)\;12 kg \]

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Let new mass be $m_1$

$mg-N=ma_1$

$30 \times 9.8-N=30 \times 1.8$

$N=30 \times (9.8-1.8)$

$\quad= 30 \times 8$

$N-m_1g=m_1a_2$

$30 \times 8 -m_1 \times 9.8 =m_1 2.2$

$m_1=\large\frac{30 \times 8}{(9.8+2.2)}$

$\qquad=\large\frac{30 \times 8}{12}$

$\qquad=20\;kg$

So the mass removed $=30-20=10\;kg$

Hence b is the correct answer.

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