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Questions  >>  CBSE XII  >>  Math  >>  Application of Integrals
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Find the area of the region lying in the first quadrant and bounded by $y = 4x^2, x = 0, y = 1$ and $y = 4$.

$\begin{array}{1 1} \frac{7}{3} \;sq.units \\ \frac{5}{3} \;sq.units \\ \frac{11}{3}\;sq.units \\ \frac{10}{3}\;sq.units \end{array} $

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