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# In a hydrogen,if energy of an electron in the ground state is 13.6 eV, then that in the 2nd excited state is

$\begin{array}{1 1}(a)\;1.51 \;eV\\(b)\;3.4\; eV\\(c)\;6.04\; eV\\(d)\;13.6\; eV\end{array}$

$E_n=\frac{13.6}{n^2} eV$
or $E=\frac{13.6}{9}eV = 1.5eV$