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# The de Broglie wavelength of a tennis ball of mass 60g movig with a velocity of 10 metres per second is approximately. Planck's constant, $h= 6.63\times10^{-34}Js$

$\begin{array}{1 1}(a)\;10^{-31}\;metres\\(b)\;10^{-16}\;metres\\(c)\;10^{-25}\;metres\\(d)\;10^{-34}\;metres\end{array}$

$\lambda=\frac{h}{mv}$
$=\large\frac{6.6\times10^{-34}}{{60\times10^{-3}}\times{10}}$
$=10^{-33}m$