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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
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Ten one rupee coins are put on top of each other on a table. Each coin has mass 'm' kg. What is the reaction of 6th coin counted from bottom on the 7th coin counted from bottom

\[(a)\;4 \;mg \quad (b)\;5\;mg \quad (c)\;6\;mg \quad (d)\;7mg \]

Can you answer this question?
 
 

1 Answer

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The sixth coin from bottom is 5th coin from top.Total Force on 5th coin from the top is $4mg$ => reaction force on the 7th coin from bottom or 4th from the top is also $4mg$
Hence a is the correct answer. 
answered Jul 11, 2013 by meena.p
edited May 27, 2014 by lmohan717
 

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