Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A small disc is on top of a hemisphere of radius R. What is the smallest horizontal velocity v that should be given to the disc for it to leave the hemisphere and not slide down ? (assume there is no friction)

\[(a)\;v=\sqrt {2gR}\quad (b)\;v=\sqrt {gR} \quad (c)\;v=\sqrt {2R} \quad (d)\;v=\sqrt {g^2 R} \]

Can you answer this question?

1 Answer

0 votes
At the top the normal reaction should be zero
When a velocity v is given in the horizontal direction Centripetal force acts
Therefore $mg-N=\large\frac{mv^2}{R}$
When N=0
$v=\sqrt {gR}$
answered Jul 12, 2013 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App