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# Find energy of each of the photons which correspond to light of frequency $3× 10^{15}\; Hz.$

$\begin{array}{1 1}(a)\;1.988 \times 10^{-18}\; KJ \\ (b)\;1.988 \times 10^{–18} \;J \\ (c)\;1.988 \times 10^{–10}\; J \\ (d)\;2.988 \times 10^{–18}\; J \end{array}$

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Solution :
Energy (E) of a photon is given by the expression, E=hν
Where, h = Planck’s constant = $6.626 \times 10^{–34}\; Js$
ν = frequency of light =$3 \times 10^{15} Hz$
Substituting the values in the given expression E = hv we get
$E = (6.626 \times 10^{–34}) (3 \times 10^{15})$
$E = 1.988 \times 10^{–18} J$