Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A block of mass 1 kg lies on a horizontal surface in a truck the coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is $5m/s^2$, the frictional force acting on the block is

\[(a)\;5N\quad (b)\;6N \quad (c)\;10N \quad (d)\;15 N \]
Can you answer this question?

1 Answer

0 votes
The maximum frictional force acting will be $\mu mg=6N$
But pseudo force acting on the body is $ma=1 \times5=5N$
Since pseudo force < frictional force
the frictional force acting is only $5N$
Hence a is the correct answer. 


answered Jul 12, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App