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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A block of mass 1 kg lies on a horizontal surface in a truck the coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is $5m/s^2$, the frictional force acting on the block is

\[(a)\;5N\quad (b)\;6N \quad (c)\;10N \quad (d)\;15 N \]
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1 Answer

The maximum frictional force acting will be $\mu mg=6N$
But pseudo force acting on the body is $ma=1 \times5=5N$
Since pseudo force < frictional force
the frictional force acting is only $5N$
Hence a is the correct answer. 

 

answered Jul 12, 2013 by meena.p
edited Feb 10, 2014 by meena.p
 

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