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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A self propelled car (point mass) runs on a track with constant speed V It passes through three positions A,B, and C on the circular part of track. Suppose $N_A\;N_B$ and $N_C$ are normal force exerted by the track on the car. When passing through A,B, and C respectively then

\[(a)\;N_A=N_B=N_C\quad (b)\;N_B > N_A > N_C \quad (c)\;N_C >N_A>N_B \quad (d)\;N_B>N_C > N_A \]

1 Answer

At any point
$mg \cos \theta-N=\large\frac{mv^2}{R}$
$N=mg \cos \theta-\large\frac{mv^2}{R}$
N decreases as $\theta$ increases
Therefore $N_B > N_A > N_C$
Hence b is the correct answer.
answered Jul 16, 2013 by meena.p
edited Feb 10, 2014 by meena.p
 

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