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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A cyclist moves in circular path of radius $100 m$ If the coefficient of friction is 0.2, then the maximum velocity with which the cyclist must take the turn with leaning inwards

\[(a)\;9.8 m/s\quad (b)\;1.4 m/s \quad (c)\;140 m/s\quad (d)\;14 m/s\]

1 Answer

$v=\sqrt {\mu r g}$
$\quad=\sqrt {0.2 \times 100 \times 10}$
$\quad=10 \sqrt 2$
$\quad=14 m/s$
Hence d is the correct answer. 

 

answered Jul 12, 2013 by meena.p
edited Feb 10, 2014 by meena.p
 

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