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# A circket ball of mass 150 g is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of $20 m/s$ .Force on the ball acts for 0.01s, the average force exerted by the bat on the ball

$(a)\;48 \;N\quad (b)\;480\;N \quad (c)\;40\;N\quad (d)\;400\;N$
Can you answer this question?

## 1 Answer

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$Force=\large\frac{Finace\; momentum-Initial\; momentum}{time}$
$\qquad=\large\frac{\Large\frac{150}{1000} \times 12 -\Large\frac{150}{1000} (-20)}{0.01}$
$\qquad=\large\frac{4.8}{.01}$
$\qquad=480 \;N$
answered Jul 12, 2013 by
edited May 27, 2014

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