Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A body is suspended by a string from the ceiling of an elevator. It is observed that the tension in the string is doubled when the elevator is accelerated. The acceleration will be

\[(a)\;4.9\; m/s^2 \quad (b)\;9.8\; m/s^2 \quad (c)\;19.6 \; m/s^2 \quad (d)\;2.45\; m/s^2\]

Can you answer this question?

1 Answer

0 votes
Let $a_0$ be acceleration of the elevator
$T=2 T_0$
Also $T=T_0\bigg(1+\large\frac{a_0}{g}\bigg)$
Therefore $ 2= 1+\large\frac{a_0}{g}$
Hence b is the correct answer. 


answered Jul 14, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App