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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

The position x of a body of mass 2 kg various with time as $x=2t^2+3t-4$. Find the force acting on the body

\[(a)\;10\;N \quad (b)\;9\;N \quad (c)\;6\;N \quad (d)\;8\;N\]

1 Answer

Velocity $v=\large\frac{dx}{dt}$$=4t+3$
acceleration $a= \large\frac{dv}{dt}$$=4\; m/s^2$
Force $=m \times a$
$\qquad= 2 \times 4$
$\qquad = 8 N$
Hence d is the correct answer.

 

answered Jul 15, 2013 by meena.p
edited Feb 10, 2014 by meena.p
 

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