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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

Sand is dropped on a conveyor belt at rate of M kg/s Force necessary to keep the belt moving with a constant velocity v m/s will be

\[(a)\;zero \quad (b)\;Mv\;N \quad (c)\;2\;Mv\;N \quad (d)\;\frac{Mv}{2}\;N\]

1 Answer

Force $=\large\frac{d}{dt}$$(mv)$
$\qquad=v \large\frac{dm}{dt}$ as v is constant
Therefore $F=Mv $ N
Hence b is the correct answer.
answered Jul 15, 2013 by meena.p
edited May 28, 2014 by lmohan717
 

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