Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A car of 1000 kg with velocity 18 km/hr is stopped by brake of 1000 N. distance covered by it before stopping is

\[(a)\;1\;m \quad (b)\;12.5\;m \quad (c)\;162\;m \quad (d)\;144\;m\]
Can you answer this question?

1 Answer

0 votes
$\quad=-1 m/s^2$
$0=\bigg(\large\frac{5}{18} $$ \times 18\bigg)^2-2s$
$s=12.5\; m$
Hence b is the correct answer. 


answered Jul 15, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App