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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
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A monkey of mass $20\; kg$ is holding a vertical rope. The rope will not break when mass of $25\; kg$ is suspended from it. but will break if the mass exceeds $25\; kg$. what is the accelerations (maximum) with which the monkey can climb up along the rope. $(g=10 m/s^2)$

\[(a)\;10\; m/s^2 \quad (b)\;2.5\; m/s^2 \quad (c)\;25\; m/s^2 \quad (d)\;5\;m/s^2\]
Can you answer this question?
 
 

1 Answer

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Let the Monkey be climbing up with an acceleration 'a'.
Tension in string $=m(g+a)$
=Breaking force
$20(g+a)=25 \times g$
$a=\large\frac{g}{4}$
$\quad=\large\frac{10}{4}$
$\quad=2.5 m/s^2$
Hence b is the correct answer.

 

answered Jul 15, 2013 by meena.p
edited Feb 10, 2014 by meena.p
 

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