Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion
Answer
Comment
Share
Q)

A monkey of mass $20\; kg$ is holding a vertical rope. The rope will not break when mass of $25\; kg$ is suspended from it. but will break if the mass exceeds $25\; kg$. what is the accelerations (maximum) with which the monkey can climb up along the rope. $(g=10 m/s^2)$

\[(a)\;10\; m/s^2 \quad (b)\;2.5\; m/s^2 \quad (c)\;25\; m/s^2 \quad (d)\;5\;m/s^2\]

1 Answer

Comment
A)
Let the Monkey be climbing up with an acceleration 'a'.
Tension in string $=m(g+a)$
=Breaking force
$20(g+a)=25 \times g$
$a=\large\frac{g}{4}$
$\quad=\large\frac{10}{4}$
$\quad=2.5 m/s^2$
Hence b is the correct answer.

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...