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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2004
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Q)

The phase difference between two waves, <br> $y_{1}=10^{-6} \sin \{100t+(x/50)+0.5\}m$ <br> $y_2=10^{-6} \cos \{100t+(\frac{ x} {50})\}m$ <br> Where X is expressed in metres and t is expressed in seconds, is approximately : -


( A ) 1.5 radians
( B ) 1.07 radians
( C ) 2.07 radians
( D ) 0.5 radians

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