a) remains constant b) first remains constant then decreases c) first decreases then increases d) first increases then decreases

Till $\theta < \tan ^{-1} \mu$ contact force is constant and gravitational force are equal and opposite.

Once the body starts sliding

$F_c=\sqrt {(mg \cos \theta)^2+(\mu \;mg\; \cos \theta)^2}$

$\quad= mg \cos \theta \sqrt {1+\mu ^2}$

So as $\theta $ increases $\cos \theta$ decreases.

So contact force decreases.

Hence b is the correct answer.

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