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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
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A body is placed on rough inclined plane of inclination $\theta$. As angle $\theta$ is increased from $0^{\circ}$ to $ 90^{\circ}$ the contact force between the block and plane

a) remains constant b) first remains constant then decreases c) first decreases then increases d) first increases then decreases
Can you answer this question?
 
 

1 Answer

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Till $\theta < \tan ^{-1} \mu$ contact force is constant and gravitational force are equal and opposite.
Once the body starts sliding
$F_c=\sqrt {(mg \cos \theta)^2+(\mu \;mg\; \cos \theta)^2}$
$\quad= mg \cos \theta \sqrt {1+\mu ^2}$
So as $\theta $ increases $\cos \theta$ decreases.
So contact force decreases.
Hence b is the correct answer.

 

answered Jul 15, 2013 by meena.p
edited Mar 21, 2014 by thagee.vedartham
 

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