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Questions  >>  SAT  >>  Math  >>  Quadratic Equations
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$36x^2-12x-15=0$ solve for $x$

$\begin{array}{1 1} (a)\;\frac{1}{2},\frac{1}{3} \\ (b)\;\frac{-1}{2},\frac{-1}{3} \\ (c)\;\frac{-1}{2},\frac{5}{6} \\(d)\;\frac{1}{2},\frac{5}{6}\end{array} $

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