Consider the reaction<br> $N_2(g)+3H_2(g)\to2NH_3(g)$ <br> The equality relationship between $\frac{d[NH_3]}{dt}$ and $\frac{-d[H_2]}{dt}$is :-

Question

( A ) $\frac {d[NH_3]}{dt}= \frac {d[H_2]}{dt}$
( B ) $\frac {d[NH_3]}{dt}=\frac {1}{3} \frac {d[H_2]}{dt}$
( C ) $\frac {d[NH_3]}{dt}=\frac {2}{3} \frac {d[H_2]}{dt}$
( D ) $\frac {d[NH_3]}{dt}=\frac {3}{2} \frac {d[H_2]}{dt}$