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# Work done by force $F=(-6x^3\hat i)\;N$ in displaying particle from $x=4m$ to $x=-2m$ is

$(a)\;240\;J \quad (b)\;360\;J \quad (c)\;420\;J \quad (d)\;will \;depend\;on\;path$

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## 1 Answer

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Answer: 360 J
$W=\int F.dx =\int \limits_{4} ^{-2} -6x^3 dx$