Comment
Share
Q)

# Work done by force $F=(-6x^3\hat i)\;N$ in displaying particle from $x=4m$ to $x=-2m$ is

$(a)\;240\;J \quad (b)\;360\;J \quad (c)\;420\;J \quad (d)\;will \;depend\;on\;path$

$W=\int F.dx =\int \limits_{4} ^{-2} -6x^3 dx$
\$\quad=\large\frac{-3}{2} $$x^4 \bigg|_4^{-2} = \large\frac{-3}{2}$$ [16-256] = 360.