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# Maximum number of electrons in a subshell of an atom is determined by the following

$\begin{array}{1 1} (a)\;4l+2 \\ (b)\;2l+1 \\ (c)\;4l-2 \\ (d)\;2n^2 \end{array}$

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Solution :
Total number of subshells$=(2l+1)$
therefore ,
Maximum number of electron in the subshell $=2(2l+1)=4l+2$
Total number of subshells $=(2l+l)$
therefore maximum number of electrons in the subshell $=2(2l+1)=4l+2$