Answer: 90 J

Work is done by a force on a body over a certain displacement. $W = F\; s$

In this case $F = 0.5 N$. We need to calculate displacement and then Work.

Given $F = 0.5N$ and mass $m = 5Kg \rightarrow$ Acceleration $a = \large\frac{F}{m}$$ = \large\frac{0.5}{5}$$ = 0.1\;m/s^2$

Given $t = 1m = 60s$ and Initial velocity $u = 0\;m/s$, we can calculate Displacement $s = ut + \large\frac{1}{2}$$ut^2$$ = \large\frac{1}{2}$$ (0.1\; m/s^2)(60^2 s^2)$$ = 180m$

Hence work done $ = F\;s = 0.5N \times 180m = 90J$