$\begin{array}{1 1} (a)\;ns \to (n-1)d \to (n-2)f \to np \\ (b)\;ns - (n-2)f \to np \to (n-1)d \\ (c)\;ns - np \to (n-1)d \to (n-2)f \\ (d)\;ns \to (n-2)f \to (n-1)d \to np \end{array} $

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