\[(a)\;147.5\;J,-122.5\;J \quad (b)\;122.5\;J,-147.5\;J \quad (c)\;95.5\;J,20.5\;J \quad (d)\;25\;J,-25\;J\]

From the free body diagram, $T-mg=5a$

$\Rightarrow T=5(9.8+2) = 59 N$

The force T and the displacement are in the same direction.

Therefore, the Work done by tension $ = Ts \cos 0^\circ = 59 \times 2.5 \times 1 = 147.5J$ (here s = 2.5 m, the distance moved by the block)

The gravitational force $mg$ and the displacement are in the opposite direction.

Work done against gravity $=-mgs =5 \times 9.8 \times 2.5 = -122.5J$

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