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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
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A block of weight $W$ is pulled along a distance $d$ on a table. The work done by the weight is

\[(a)\;Wd\quad (b)\;0 \quad (c)\;Wgd \quad (d)\;Wd/g\]

Can you answer this question?
 
 

1 Answer

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Answer: 0.
Since the work done on the weight is perpendicular to the direction of displacement $\theta = 90^\circ$
Work done = $F.d \cos \theta$. Since $\cos \theta = 0$, work done $=0$
answered Jul 17, 2013 by meena.p
edited Aug 25, 2014 by balaji.thirumalai
 

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