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A ball is dropped from a height of h from ground. If the coefficient of restitution is e, the height to which the ball goes up after it rebounds for the nth time is

\[(a)\;e^{2n}h \quad (b)\;he^n \quad (c)\;he^{2n} \quad (d)\;h/e^{2n}\]

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For an object bouncing off a stationary object, such as a floor, coefficient of restitution, $e = \sqrt{\large \frac{h'}{h}}$
$\Rightarrow$ The height to which it bounces $h' = e^2h$
Similarly, after it rebounds for the nth time, the height to which it rises $h' = e^{2n}h$
Answer: $e^{2n}h$
answered Jul 17, 2013 by meena.p
edited Aug 25, 2014 by balaji.thirumalai

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