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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2008
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Q)

In an A.C. circuit the emf (e) and the current (i) at any instant are given respectively by : <br> $e=E_0 \sin \omega t$ <br> $i=I_0 \sin(\omega t-\phi)$ <br>The average power in the circuit over one cycle of A.C. is -


( A ) $E_0 I_0$
( B ) $\frac{E_0 I_0}{2} \sin \phi$
( C ) $\frac{E_0 I_0}{2}$
( D ) $\frac{E_0 I_0}{2} \cos \phi $

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A)
Pavg=vĂ—icos(thita) Pav=E.i./2cos(phi)
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