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# Calculate work done to move a body of mass 10 kg along an incline $(\theta=30^{\circ})$ with constant velocity through a distance 10 m $(g=10 m/s^2)$

$(a)\;1000 \;J \quad (b)\;500 \;J\quad (c)\;250\;J \quad (d)\;10\; J$

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## 1 Answer

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We need to apply an external force, $F=mg \sin \theta$ up the plane, while the body is in motion downwards.
$\Rightarrow W = F\;d = mg \sin \theta \; d$
Given $d=10\;m, m = 10 Kg, \theta = 30^\circ, g = 10 m/s^2$,
$W=10 \times 10 \times \sin 30 \times 10$
$\quad=100 \times \large\frac{1}{2}$$\times 10$
$\quad=500\;J$
answered Jul 18, 2013 by
edited Aug 25, 2014

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