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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2008
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Q)

On the basis of the following Eº values, the strongest oxidizing agent is : $[Fe(CN)_6]^{4-}\rightarrow[Fe(CN)_6]^{3-}+e^{-1},E^o=-0.35v$ $Fe^{2+}\rightarrow Fe^{3+}+e^{-1},E^o=-0.77v$


( A ) $[Fe(CN)_6]^{4–}$
( B ) $Fe^{2+}$
( C ) $[Fe(CN)_6]^{3–}$
( D ) $Fe^{3+}$

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