\[(a)\;100 \;J \quad (b)\;300\;J\quad (c)\;50\;J \quad (d)\;125\; J\]

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Since it is acted upon simultaneously by two forces 4N and 3N at right angles, net force $=\sqrt {4^2+3^2} = 5N$

The mass is given as $10\;Kg \rightarrow \;a=\large\frac{F}{m}$$ =\large\frac{5}{10} $$ = 0.5\;m/s^2$

Now, we can calculate the Kinetic Energy as $K.E=\large\frac{1}{2} $$mv^2=\large\frac{1}{2}$$m(at)^2$

$\Rightarrow KE =\large\frac{1}{2}$$10 \times 0.5^2 \times 10 s$$ = 125 J$

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